1.

Find the value of p if x³ - px +10x² - 6 =5 for x =-1​

Answer»

<P>Given,

  • Value of X {for which p(x) is 0} = -1

\rm{}p(x) = {x}^{3} - px + {10x}^{2} - 6

To FIND : Value of p in p(x)

✓✓ SOLUTION ✓✓

Putting the value of x in p(x), we GET,

\tt = > {( - 1)}^{2} - p( - 1) + {10( - 1)}^{2} - 6 = 0 \\ \tt = > \: \: \: \: - 1 + p + 10 - 6 = 0 \\ \tt = > \: \: \: \: \: p + 10 - 7 = 0 \\ \tt = > \: \: \: \: \: p + (10 - 7) = 0 \\ \tt= > \: \: \: \: p + 3 = 0 \\ \tt = > \: \: \: \: \: \: \: \: \: \: \: p = - 3

Hence,

  • Required value of p is -3


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