1.

Find the value of R in Fig. so that there is no current in the 15Omega resistor.

Answer»

Solution :This is the Wheatstone bridge with the GALVANOMETER REPLACED by `15Omega` resistor. There bridge is balanced because there is no CURRENT in `15Omega` resistor, hence,
`20//10=40R""THEREFORE R=(40xx10Omega)/(20)=20Omega`.


Discussion

No Comment Found

Related InterviewSolutions