1.

Find the value of sin 405°

Answer»

To find: Value of sin 405°

We have,

sin 405° = sin [90° × 4 + 45°]

= sin 45°

[Clearly, 405° is in Ist Quadrant and the multiple of 90° is even]

\(\frac{1}{\sqrt{2}}\) [∵ sin45° = \(\frac{1}{\sqrt{2}}\)]



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