Find the value of sin15°. 1. (√3 + 1)/2√22. (√3 + 1)/23. (√3

1.	Find the value of sin15°. 1. (√3 + 1)/2√22. (√3 + 1)/23. (√3 – 1)/2√24. (√3 – 1)/2
Answer» Correct Answer - Option 3 : (√3 – 1)/2√2 Formula Used: sin(A – B) = sinA × cosB – sinB × cosA Calculation: Now, from the above used formula ⇒ sin15° = sin(45° – 30°) ⇒ sin45° × cos30° – sin30° × cos45° ⇒ (1/√2) × (√3/2) – (1/√2) × (1/2) ⇒ (√3 – 1)/(2 × √2) ∴ (√3 – 1 )/ 2√2

Find the value of sin15°. 1. (√3 + 1)/2√22. (√3 + 1)/23. (√3 – 1)/2√24. (√3 – 1)/2

Answer» Correct Answer - Option 3 : (√3 – 1)/2√2

Formula Used:

sin(A – B) = sinA × cosB – sinB × cosA

Calculation:

Now, from the above used formula

⇒ sin15° = sin(45° – 30°)

⇒ sin45° × cos30° – sin30° × cos45°

⇒ (1/√2) × (√3/2) – (1/√2) × (1/2)

⇒ (√3 – 1)/(2 × √2)

∴ (√3 – 1 )/ 2√2