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Find the value of `sin37(1/2)^(@).sin7 (1/2)^(@)` |
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Answer» `sin37 (1/2)^(@). Sin7(1/2)^(@)` `=1/2.2sin37 (1/2)^(@).sin 7(1/2)^(@)` `=1/2.[cos37(1/2)^(@)-7(1/2)^(@)-cos37(1/2)^(@)+7(1/2)^(@)]` `=1/2(cos30^(@)-cos45^(@))` `=1/2(sqrt(3)/2-1/sqrt(2))=(sqrt(3)-sqrt(2))/(4)` Ans. |
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