1.

Find the value of \(\sqrt{12}\) - 1/√3 correct to two decimal places.

Answer»

\(\sqrt{12}-\frac{1}{\sqrt{3}}=\frac{2\sqrt{3}}1{}-\frac{1}{\sqrt{3}}\)\(=\frac{6}{\sqrt{3}}-\frac{1}{\sqrt{3}}=\frac{5}{\sqrt{3}}\)

\(\frac{5}{1.73}\) = 2.89



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