1.

Find the value of the following if ∆ABC = ∆PRQ as given below :(i) Side PR(ii) Side QR(iii) Side PQ(iv) ∠P(v) ∠Q(vi) ∠R

Answer»

In ∆ABC

∠A + ∠B + ∠C = 180°
45° + 65° + ∠C = 180°
110° + ∠C = 180°
∠C = 180° – 110° = 70°

In ∆ABC and ∆PRQ

(i) side PR = side AB = 3.5 cm
(ii) side QR = side CB = 2 cm
(iii) side PQ = side AC = 2.9 cm
(iv) ∠P =∠A = 45°
(v) ∠Q =∠C = 70°
(vi) ∠R = ∠B = 65°



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