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Find the value of x, if `[1x1][{:(1,3,2),(2,5,1),(15,3,2):}][{:(1),(2),(x):}]=O.` |
Answer» We have `[1x1]_(1xx3)[{:(1,3,2),(2,5,1),(15,3,2):}]_(3xx3)[{:(1),(2),(x):}]_(3xx1)=O` `implies" "[1+2x+15" "3+5x+3" "2+x+2][{:(1),(2),(x):}]=O` `implies" "[16+2x" "6+5x" "4+x][{:(1),(2),(x):}]=O` `implies" "[(16+2x).1+(6+5x).2+(4+x).x]=O` `implies" "(16+2x)+(12+10x)+(4x+x^(2))=0` `implies" "x^(2)+16x+28=0` `implies" "(x+14)(x+2)=0` `implies" "x+14=0" or "x+2=0` `implies" "x=-14" or "x=-2.` Hence, `x=-14" or "x=-2.` |
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