1.

Find the value of x, if `[1x1][{:(1,3,2),(2,5,1),(15,3,2):}][{:(1),(2),(x):}]=O.`

Answer» We have
`[1x1]_(1xx3)[{:(1,3,2),(2,5,1),(15,3,2):}]_(3xx3)[{:(1),(2),(x):}]_(3xx1)=O`
`implies" "[1+2x+15" "3+5x+3" "2+x+2][{:(1),(2),(x):}]=O`
`implies" "[16+2x" "6+5x" "4+x][{:(1),(2),(x):}]=O`
`implies" "[(16+2x).1+(6+5x).2+(4+x).x]=O`
`implies" "(16+2x)+(12+10x)+(4x+x^(2))=0`
`implies" "x^(2)+16x+28=0`
`implies" "(x+14)(x+2)=0`
`implies" "x+14=0" or "x+2=0`
`implies" "x=-14" or "x=-2.`
Hence, `x=-14" or "x=-2.`


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