1.

Find the value of x if \(\begin{vmatrix}3&x\\2&x^2 \end{vmatrix}\)=\(\begin{vmatrix}5&3\\3&2\end{vmatrix}\).(a) x=1, –\(\frac{1}{3}\)(b) x=-1, –\(\frac{1}{3}\)(c) x=1, \(\frac{1}{3}\)(d) x=-1, \(\frac{1}{3}\)I got this question in class test.This question is from Determinant in section Determinants of Mathematics – Class 12

Answer»

The correct choice is (a) X=1, –\(\frac{1}{3}\)

For EXPLANATION I would say: GIVEN that \(\begin{vmatrix}3&x\\2&x^2 \end{vmatrix}\)=\(\begin{vmatrix}5&3\\3&2\end{vmatrix}\)

⇒3x^2-2x=5(2)-3(3)

⇒3x^2-2x=1

Solving for x, we get

x=1, –\(\frac{1}{3}\).


Discussion

No Comment Found

Related InterviewSolutions