1.

Find the value of x if \(\big[3^{2x-2}+10\big]\) ÷ 13 = 7.(a) 1 (b) 3 (c) 4 (d) 2

Answer»

(b) 3

  \(\big[3^{2x-2}+10\big]\) ÷ 13 = 7.

⇒ 32x – 2 + 10 = 7 × 13 = 91

⇒ 32x – 2 = 91 – 10 = 81 = 34

⇒ 2x –2 = 4 ⇒ 2x = 6 ⇒ x = 3.



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