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Find the value of x if \(\big[3^{2x-2}+10\big]\) ÷ 13 = 7.(a) 1 (b) 3 (c) 4 (d) 2 |
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Answer» (b) 3 \(\big[3^{2x-2}+10\big]\) ÷ 13 = 7. ⇒ 32x – 2 + 10 = 7 × 13 = 91 ⇒ 32x – 2 = 91 – 10 = 81 = 34 ⇒ 2x –2 = 4 ⇒ 2x = 6 ⇒ x = 3. |
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