1.

Find the value of Y-X if ABCD is a rhombus in the figure given belowplease answer fast​

Answer»

Answer:

AB||CD (Opposite SIDES of Rhombus are parallel)

ANG CAB = ang DCA (Alternate INTERIOR angles)

Given, ang CAB = 40°

So, ang CAB = ang DCA = 40°

ang CDB + ang DCA = ang COB (Exterior Angle PROPERTY)

x + 40° = y (ang CDB = x, ang DCA = 40°, ang COB = y)

40° = y-x

Hence, 40° is the answer.



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