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Find the values of a, b and c if matrices A and B are equal, whereA = \(\begin{bmatrix}a - 2&3&2c\\[0.3em]12c& b + 2 & bc\end{bmatrix}, B = \begin{bmatrix}b&c&6\\[0.3em]6b&a&3b\end{bmatrix}\) |
Answer» Given, A = B A = \(\begin{bmatrix}a - 2&3&2c\\[0.3em]12c& b + 2 & bc\end{bmatrix}, B = \begin{bmatrix}b&c&6\\[0.3em]6b&a&3b\end{bmatrix}\) On comparing a – 2 = b ⇒ a – b = 2 …..(i) 3 = c 12c = 6b ⇒ b = (12 x 3)/6 = 6 ⇒ b = 6 From b + 2 = a, a – b = 2 ∴ a = 2 + b = 2 + 6 = 8 So, a = 8, b = 6, c = 3. |
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