Find the values of the following : i) `tan (19pi)/3` ii) `sec(-22pi)/3

1.	Find the values of the following : i) `tan (19pi)/3` ii) `sec(-22pi)/3`
Answer» i) `tan(19pi)/3= tan(19 xx 180^(@))/(3)` `=tan(1140^(@))` `=tan(3 xx 360^(@) +60^(@))` `=tan60^(@)=sqrt(3)` ii) `sec(-22pi)/(3)=sec(22pi)/(3)=sec(22 xx 180^(@))/(3)` `=sec1320^(@)` `=sec(3 xx 360^(@) + 240^(@))` `=sec240^(@)=sec(180^(@)+60^(@))` `=-sec60^(@)=-2` Ans.

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