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Find the values of the following trigonometric ratios:cos \(\cfrac{19\pi}6\) |
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Answer» Given cos \(\cfrac{19\pi}6\) ⇒ cos \(\cfrac{19\pi}6\) = cos 570° ⇒ 570° = (90° × 6 + 30°) 570° lies in third quadrant in which cosine function is negative. ∴ cos (570°) = cos (90° × 6 + 30°) = -cos (30°) = \(-\cfrac{\sqrt3}2\) |
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