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Find the values of the following trigonometric ratios:sin(\(\cfrac{41\pi}4\)) |
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Answer» Given sin(\(\cfrac{41\pi}4\)) ⇒ sin(\(\cfrac{41\pi}4\)) = sin 1845° ⇒ sin 1845° = 90° × 20 + 45° 1845° lies in the first quadrant in which the sine function is positive. ∴ sin 1845° = sin (90° × 20 + 45°) = sin 45° = \(\cfrac1{\sqrt2}\) |
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