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Find the values of the following trigonometric ratios:cosec (-\(\cfrac{20\pi}3\)) |
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Answer» Given cosec (-\(\cfrac{20\pi}3\)) ⇒ cosec (-\(\cfrac{20\pi}3\)) = cosec(-1200°) ⇒ cosec (-1200°) = cosec (1200°) = cosec (90° × 13 + 30) 1200° lies in second quadrant in which cosec function is positive. ∴ cosec (-1200°) = -cosec (90° × 13 + 30°) = -sec 30° = \(-\cfrac{2}{\sqrt3}\) |
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