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Find the values of the following trigonometric ratios:sin\(\cfrac{17\pi}6\) |
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Answer» Given sin \(\cfrac{17\pi}6\) ⇒ sin \(\cfrac{17\pi}6\) = sin 510° ⇒ 510° = (90° × 5 + 60°) 510° lies in second quadrant in which sine function is positive. ∴ sin (510°) = sin (90° × 5 + 60°) = cos (60°) = 1/2 |
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