1.

Find the values of the following trigonometric ratios:sin\(\cfrac{17\pi}6\)

Answer»

Given sin \(\cfrac{17\pi}6\)

 ⇒ sin \(\cfrac{17\pi}6\) = sin 510°

⇒ 510° = (90° × 5 + 60°)

510° lies in second quadrant in which sine function is positive.

∴ sin (510°) = sin (90° × 5 + 60°)

= cos (60°) = 1/2



Discussion

No Comment Found