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Find the values of the following trigonometric ratios:sin(\(-\cfrac{11\pi}6\)) |
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Answer» Given sin \((\cfrac{-11\pi}6)\) ⇒ sin \(\cfrac{-11\pi}6\) = sin -330° ⇒ -sin 330° = -sin (90° × 3 + 60°) 330° lies in the fourth quadrant in which the sine function is negative. ∴ sin (-330)° = -sin (90° × 3 + 60°) = - (-cos 60°) = - (-1/2) = 1/2 |
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