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Find the values of the following trigonometric ratios:sin \(\cfrac{151\pi}6\) |
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Answer» Given sin \(\cfrac{151\pi}6\) ⇒ sin \(\cfrac{151\pi}6\) = sin 4530° ⇒ sin 4530° = 90° × 50 + 30° 4530° lies in the third quadrant in which the sine function is negative. ∴ sin 4530° = sin (90° × 50 + 30°) = - sin 30° = -1/2 |
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