1.

Find the values of the following trigonometric ratios:sin \(\cfrac{151\pi}6\)

Answer»

Given sin \(\cfrac{151\pi}6\)

⇒ sin \(\cfrac{151\pi}6\) = sin 4530°

⇒ sin 4530° = 90° × 50 + 30°

4530° lies in the third quadrant in which the sine function is negative.

∴ sin 4530° = sin (90° × 50 + 30°)

= - sin 30°

= -1/2



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