find the vector equation of the line passing through the point (-1, 5,

1.	find the vector equation of the line passing through the point (-1, 5,4) and perpendicular to the plane z=0
Answer» Hey mate, here you go, Solution : the line passing through (-1, 5, 4) and PERPENDICULAR to the plane z = 0. the line will be parallel to normal of the plane. THEREFORE the required equation of the line is -i + 5j + 4k + λ(0i + 0j + k) in vector form. hope it HELPS you! Have a cheerful day! (^_^)

find the vector equation of the line passing through the point (-1, 5,4) and perpendicular to the plane z=0

Answer»

Hey mate, here you go,

Solution : the line passing through (-1, 5, 4) and PERPENDICULAR to the plane z = 0. the line will be parallel to normal of the plane. THEREFORE the required equation of the line is -i + 5j + 4k + λ(0i + 0j + k) in vector form.

hope it HELPS you! Have a cheerful day! (^_^)

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find the vector equation of the line passing through the point (-1, 5,4) and perpendicular to the plane z=0​

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find the vector equation of the line passing through the point (-1, 5,4) and perpendicular to the plane z=0