1.

Find the vector equation of the line which passes through the point with position vector `4hati - hatj + 2 hat k` and is in the direction of ` - 2hati + hatj + hat k`.

Answer» The vector equation of a line passing through a point with position vector `bar a` and parallel to ` bar b` is given by ` bar r = bar a + lambda bar b`
Here, ` bar a = 4hati - hatj + 2hatk and bar b = - 2 hat I + hat j + hat k`.
Hence , the required vector equation is
`barr = (4hati- hatj+2hatk)+ lambda(-2hati+hatj+hatk)`


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