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Find the vector equation ofa line passing through `3 hat i-5 hat j+7 hat k`and perpendicular totheplane `3x-4y+5z=8.` |
Answer» The given plane `3x-4y+5z=8 or (3hati-4hatj+5hatk)*(xhati+yhatj+7hatk)=8.` This shows that `vecd=3hati-4hatj+5hatk` is normal to the given plane. Therefore, the required line is parallel to `3hati-4hatj+5hatk`. Since the required line passes through `3hati-5hatj+7hatk`, its equation is given by `" "vecr=3hati-5hatj+7hatk+lamda(3hati-4hatj+5hatk),` where `lamda` is a parameter. |
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