InterviewSolution
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InterviewSolution
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Find the vector equationof the line passing through the point `(1," "2," "" "4)`and perpendicular to the two lines: `(x-8)/3=(y+19)/(-16)=(z-10)/7`and `(x-15)/3=(y-29)/8=(z-5)/(-5)` |
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Answer» Since the line to be determined is perpendicular to the given two straight lines, it is directed towards `" ""Vector "(3hati-16hatj+7hatk)xx(3hati+8hatj-5hatk)` `=|{:(hati,,hatj,,hatk),(3,,-16,,7),(3,,8,,-5):}|=24hati+36hatj+72hatk` Therefore, direction ratios of the line are 24, 36, 72 or 2, 3, 6. Hence, equation of line passing through the point (1, 2, -4) and parallel to the vector `2hati+3hatj+6hatk` is `" "vecr=(hati+2hatj-4hatk)+lamda(2hati+3hatj+6hatk)` This is the equation of the required line. |
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