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Find the vector potential when the field intensity 60x^2 varies from (0,0,0) to (1,0,0).(a) 120(b) -20(c) -180(d) 60I had been asked this question at a job interview.The above asked question is from Magnetic Vector Potential in division Magnetostics of Electromagnetic Theory

Answer»

Right answer is (b) -20

The EXPLANATION is: The FIELD intensity H = -GRAD(V). To get V, integrate H with respect to the variable. Thus V = -∫H.dl = -∫60x^2 DX = -20x^3 as x = 0->1 to get -20.


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