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Find the virtual height h when the angle of incidence is 600 and distance of separation 120km.(a) 60km(b) 64.34km(c) 34.64km(d) 72.42kmI have been asked this question during an interview.This interesting question is from Virtual Height in portion Virtual Height, Critical Frequency and Muf of Antennas

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Correct ANSWER is (c) 34.64km

Easiest explanation: VIRTUAL height \(h=\frac{d/2}{\SQRT{secθ_i^2-1}}=34.64km\)



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