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Find the wavelength of X-ray radiation if the maximum kinetic energy of compton electrons is T_(max) = 0.19 MeV. |
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Answer» Solution :We see form the previous PROBLEM that the electron GAINS the maximum `K.E.` when the photon is SCATTERED backwards `theta = 180^(@)`. Then `omega_(0) = omega_(0) = (mc^(2)//cancel h)/(sqrt(1+(2mc^(2))/(T_(max)) )-1)` Hence `lambda_(0) = (2pic)/(omega_(0)) = (2picancel h)/(mc) [sqrt(1+(2mc^(2))/(T_(max)))-1]` Substituting the values we get `= lambda_(0) = 3.695 pm`. |
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