1.

Find the work done and power of an engine which can maintain a speed of 50 ms-1 for a train of mass 3 × 106 kg on a rough level track for 5 km. The coefficient of friction is 0.05. (Giving g = 10 ms-2)

Answer»

Given : m = 3 × 106 kg, v = 50 ms-1

μ = 0.05, g = 10 ms-2

S = 5 km = 5000 m

P = ?, W = ?

F = force of friction = μmg

(Normal reaction, R = mg)

∴ P = Fv = μmgv

or P = 0.05 × 3 × 106 × 10 × 50

or P = 75 × 106 watt

or P = 75 × 103 kW

= 7.5 × 104 kW

Work done, W = FS = μmgS

or W = 0.05 × 3 × 106 × 10 × 5 × 103 J

or W = 75 × 108 J.



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