InterviewSolution
Saved Bookmarks
| 1. |
Find the work done and power of an engine which can maintain a speed of 50 ms-1 for a train of mass 3 × 106 kg on a rough level track for 5 km. The coefficient of friction is 0.05. (Giving g = 10 ms-2) |
|
Answer» Given : m = 3 × 106 kg, v = 50 ms-1 μ = 0.05, g = 10 ms-2 S = 5 km = 5000 m P = ?, W = ? F = force of friction = μmg (Normal reaction, R = mg) ∴ P = Fv = μmgv or P = 0.05 × 3 × 106 × 10 × 50 or P = 75 × 106 watt or P = 75 × 103 kW = 7.5 × 104 kW Work done, W = FS = μmgS or W = 0.05 × 3 × 106 × 10 × 5 × 103 J or W = 75 × 108 J. |
|