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Find the work done by an external agent in lowering a block of mass m slowly ona light of stiffness k, till it comes to rest. |
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Answer» Solution :`W= int F_("ext").DX=int_(0)^(x,0)(mg-kx)dx cos pi` `=-(mgx_(0)-(kx_(0)^(2))/(2))`...(a) Where `kx_(0)=(mg)/(k)`...(b) using (a) & (b) . `W_("ext")=-(m^(2)g^(2))/(2k)` 
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