1.

Find the zeroes of quadratic polynomial:x^2+7x+10​

Answer»

<P>Step-by-step explanation:

Let p(X) = x²+7x+10

We get zeroes of the polynomial

p(x) we will take p(x) = 0

=> x² + 7x + 10 = 0

=> x² + 2X + 5X + 10 = 0

=> x( x + 2 ) + 5( x + 2 ) = 0

=> ( x + 2 )( x + 5 ) = 0

=> x + 2 = 0 or x + 5 = 0

=> x = -2 or x = -5

Therefore

The zeroes of p(x) are -2 , -5

i ) Compare x²+7x+10 with ax²+bx+c

we get

a = 1 , b = 7 , c = 10

Sum of the zeroes = - 2 + ( -5 )

= -7

= ( -b/a )

ii ) Product of the zeroes

= ( -2 )( -5 )

= 10

= c/a


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