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FIND THE ZEROES OF THE FOLLOWING QUADRATIC EQUATION AND VERIFY THE RELATIONSHIP BETWEEN ZEROES AND THE COEFFICIENTS? 2 MARKS 3X^2-X-4

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Answer:

answer is,

SUM of zeroes=1/3

product of zeroes=(-4/3)

Step-by-step EXPLANATION:

GIVEN,

=3x^2-x-4

=3x^2-4x+3x-4

=x(3x-4)+1(3x-4)

=(x+1)(3x-4)

=x=4/3,(-1)

therefore alpha and beta Alpha=4/3

beta=(-1)

sum of zeroes=alpha+beta

=4/3-1

=1/3

- b/a=-(COEFFICIENT of x)/(coefficient of x^2)

=-(-1)/3

=1/3

product of zeroes=alpha×beta

=4/3×(-1)

=(-4/3)

c/a=constant/coefficient of x^2

=(-4/3)

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