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Find the zeroes of the polynomial x2-3 and verify the relation between the zeroes and thecoefficients. |
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Answer» Answer: Step-by-step EXPLANATION: x² - 2x - 8 = 0 → x² - 4x + 2x - 8 = 0 → x(x - 4) + 2(x - 4) = 0 → (x - 4)(x + 2) = 0 → x = 4 or (-2) . now, → sum of roots = (-b/a) → 4 + (-2) = -(-2)/1 → 4 - 2 = 2/1 → 2 = 2 (VERIFY) and, → Product of roots = c/a → 4 * (-2) = (-8/1) → (-8) = (-8) (verify) |
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