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Find the zeroes of the quadratic polynomial 6x2 +13x-5 and verify the zeroes and coefficient |
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Answer» We have p(X) = X2 – 2x – 8 = x2 + 2x – 4x – 8 = x (x + 2) – 4 (x + 2) = (x – 4) (x + 2) For p(x) = 0, we have (x – 4) (x + 2) = 0 EITHER x – 4 = 0 ⇒ x = 4 or x + 2 = 0 ⇒ x = – 2 ∴ The zeroes of x2 2x – 8 are 4 and –2. Now, SUM of the zeroes |
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