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find the zeros of each of the following quadratic polynomial also, in each case verify the relationship between the zeros and coefficient :x2-7x+10 |
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Answer» Answer: Given QUADRATIC POLYNOMIAL x2 + 7x + 10 Using factorisation (splitting the middle term) x2 + 7x + 10 = 0 x2 + (5X + 2x) + 10 = 0 x2 + 5x + 2x + 10 = 0 x(x + 5) + 2 (x + 5) = 0 (x + 5) (x + 2) = 0 Hence, ZEROES of a given quadratic polynomial are – 5 and – 2. Sum of zeroes = -2+(-5) = -2-5 = -7/1 = -x COEFFICIENT /x² coefficient Product of zeroes = (-2)(-5) = 10/1 = constant/x² coefficient |
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