1.

Find the zeros of the polynomial of x^2-5x+3​

Answer»

\huge\underline{ \underline{ \bf{ \red{ \: solution \: : =  }}}}

\bf {\blue{ {x }^{2} - 5x + 3 = 0 }}

By using COMPLETING the SQUARE method for solving this equation.

move constant to the right hand SIDE and CHANGE it's sign.

⠀⠀⠀⠀⠀\bf {\green{ {x}^{2} - 5x =  - 3  }}\\

Add \bf {\green{  (\frac{5}{2}  ) {}^{2} }} \\to both the sides of the equation.

\bf {\green{  {x}^{2} - 5x +  (\frac{5}{2}  ) {}^{2} =  - 3 +  (\frac{5}{2}   ) {}^{2} }}\\

Using ,

⠀⠀⠀\bf{ \boxed{ \purple{  \fbox{ {a}^{2}  +  {b}^{2} - 2ab = (a - b) {}^{2}  }}}}\\

\bf{ \green{(x -  \frac{5}{2} ) {}^{2} =  - 3 +  \frac{5}{2}  {}^{2}  }} \\

\bf {\green{(x -  \frac{5}{2} ){}^{2} =  \frac{13}{4}   }}  \\

⠀⠀⠀⠀⠀\bf{ \boxed{ \fbox {\purple{x =  \frac{ -  \sqrt{13}  + 5}{2} }}}}

⠀⠀⠀⠀⠀\bf{ \boxed{ \fbox {\purple{x =  \frac{ \sqrt{13} + 5 }{2} }}}}



Discussion

No Comment Found