find three consecutive odd integers such as the sum of forst and secon

1.	find three consecutive odd integers such as the sum of forst and second integer exceed the third integer by 19 .Now please answer tis question correctly please
Answer» Correct QUESTION: Find the three consecutive odd INTEGERS such as the sum of FIRST and second INTEGER exceed the third integer by 19. _______________________________________ Answer: $\sf{The \ three \ consecutive \ odd \ integers \ are}$ $\sf{21, \ 23 \ and \ 25.}$ Given: $\sf{In \ three \ consecutive \ odd \ integers,}$ $\sf{sum \ of \ first \ and \ second \ integer \ exceed}$ $\sf{the \ third \ integer \ by \ 19.}$ To find: $\sf{The \ three \ consecutive \ odd \ integers.}$ Solution: $\sf{Let \ the \ three \ consecutive \ odd \ integers \ be}$ $\sf{(n-2), \ n, \ and \ (n+2).}$ $\sf{According \ to \ the \ given \ condition.}$ $\sf{(n-2)+n=(n+2)+19}$ $\sf{\therefore{2n-2=n+21}}$ $\sf{\therefore{2n-n=21+2}}$ $\sf{\therefore{n=23}}$ $\sf{The \ three \ consecutive \ odd \ integers \ are}$ $\sf{n-2=23-2=21,}$ $\sf{n=23,}$ $\sf{n+2=25}$ $\sf\purple{\tt{\therefore{The \ three \ consecutive \ odd \ integers \ are}}}$ $\sf\purple{\tt{21, \ 23 \ and \ 25.}}$