1.

Find three consecutive odd numbers whose sum is 147.Hint. Let the required numbers be (2x +1), (2x +3) and (2x +5).

Answer»

Let three consecutive oddnumbers are x,x+1,x+2then=

⇒x+x+1+x+2=147

⇒3x+3=147

⇒3x=144

⇒x=48

THEREFORE NUMBERS ARE

x=48

x+1=48+1=49

x+2=48+2=50



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