1.

Find three consecutive odd numbers whose sum is 147.Hint. Let the required numbers be (2x +1), (2x +3) and (2x +5).

Answer» <p>Let three consecutive oddnumbers are x,x+1,x+2then=</p><p>⇒x+x+1+x+2=147</p><p>⇒3x+3=147</p><p>⇒3x=144</p><p>⇒x=48</p><p>THEREFORE NUMBERS ARE</p><p>x=48</p><p>x+1=48+1=49</p><p>x+2=48+2=50</p>


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