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Find three consecutive odd numbers whose sum is 147.Hint. Let the required numbers be (2x +1), (2x +3) and (2x +5). |
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Answer» Let three consecutive oddnumbers are x,x+1,x+2then= ⇒x+x+1+x+2=147 ⇒3x+3=147 ⇒3x=144 ⇒x=48 THEREFORE NUMBERS ARE x=48 x+1=48+1=49 x+2=48+2=50 |
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