Find two consecutive odd integers such that two fifth of the smaller e

1.	Find two consecutive odd integers such that two fifth of the smaller exceeds two ninth of the greater by 4
Answer» Answer: Step-by-step explanation: Solution:- Let X be the smaller odd integer and (x + 2) be the greater odd integer respectively. 2/5th of the smaller odd integer EXCEEDS 2/9th of the greater odd integer by 4. So, according to the question. 2x/5 = 2/9(x + 2) + 4 ⇒ 2x/5 = (2x + 4)/9 + 4 Taking L.C.M. of the denominators of the right side, we get. 2x/5 = (2x + 4 + 36)/9 Now, cross multiplying, we get. ⇒ (2x9) = 5*(2x + 40) ⇒ 18x = 10x + 200 ⇒ 18x - 10x = 200 ⇒ 8x = 200 ⇒ x = 200/8 ⇒ x = 25 Putting the value of x, we get x + 2 25 + 2 = 27 So, the smaller integer is 25 and the greater odd integer is 27 Answer please mark as a brainliest

Find two consecutive odd integers such that two fifth of the smaller exceeds two ninth of the greater by 4

Answer»

Answer:

Step-by-step explanation:

Solution:-

Let X be the smaller odd integer and (x + 2) be the greater odd integer respectively.

2/5th of the smaller odd integer EXCEEDS 2/9th of the greater odd integer by 4.

So, according to the question.

2x/5 = 2/9*(x + 2) + 4

⇒ 2x/5 = (2x + 4)/9 + 4

Taking L.C.M. of the denominators of the right side, we get.

2x/5 = (2x + 4 + 36)/9

Now, cross multiplying, we get.

⇒ (2x*9) = 5*(2x + 40)

⇒ 18x = 10x + 200

⇒ 18x - 10x = 200

⇒ 8x = 200

⇒ x = 200/8

⇒ x = 25

Putting the value of x, we get

x + 2

25 + 2 = 27

So, the smaller integer is 25 and the greater odd integer is 27

Answer

please mark as a brainliest