1.

Find two consecutive positive integers sum of whose squares is 365

Answer»

Heya here's the answer

let the 2 CONSECUTIVE integers are x &x+1

sum of their squares is 365

so, x² + (x+1)² = 365

=> x² + x² + 2X + 1 = 365

=> 2x² + 2x = 365 - 1 = 364

=> 2x² + 2x - 364 = 0

=> 2( x² + x - 182) = 0

=> x² + x - 182 = 0

=> x² + 14X - 13X - 182 = 0

=>( x + 14 ) (x-13 ) = 0

=> x= -14 or x= 13

since the two numbers are X and X + 1

=> x= 13 & x+1= 13+1= 14

hope it helps u

plz mark as brainlest if it helps


Discussion

No Comment Found

Related InterviewSolutions