1.

Find two consecutive positive integers, sum of whose square is 365.​

Answer»

13 and 14Step-by-step explanation:As they are CONSECUTIVE nos. So let the 1st no be (x)Then the other no. will be (x+1)Given that (x)² + (x+1)² = 365 =. x² + x² + 2x + 1 = 365 =. 2x² + 2x + 1 = 365ON HIT AND TRIAL WE GETx = 13Therefore the nos will be (x) i.e. 13 and (x+1) i.e. 14.Please do MARK as BRAINLIEST



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