1.

Find two numbers in the ratio of 8 : 7 such that when each is decreased by 12 they are in ratio 11:9. ​

Answer»

Answer:

RATIO = 8:7

Consider the numbers as 8x and 7x

They are decreased by 12

2

1

=

2

25

SP, using the condition

[7x–

2

25

]

[8x–

2

25

]

=

9

11

TAKING LCM

[

2

(14x–25)

]

[

2

(16x–25)

]

=

9

11

By further calculation

(14x–25)

(16x–25)

=

9

11

By cross multiplication

154x–275=144x–225

154x–144x=275–225

10x=50

x=

10

50

=5

So the numbers are

8x=8×5=40

7x=7×5=35


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