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Find two numbers such that the sum of twice the first and thrice the second is 92, and four times the first exceeds seven times the second by 2 |
| Answer» X=25y=14Step-by-step explanation:Let x and y be the two numbers REQUIRED. According to the question : ⇒2x+3y=92 ⇒4x−7y=2 Multiply the first equation by 2 , and subtract EQN (1) from eqn (2) 4x+6y=184 −(4x−7y=2) , we get ⇒13y=182 ⇒y= 182 / 13 = 14 Put y=14 in (1) 2x+3y=92 ⇒2x+3×14=92 ⇒2x=92−42=50 ∴x= 50 / 2 = 25 | |