InterviewSolution
Saved Bookmarks
| 1. |
Find two numbers whose arithmetic mean is 34 and the geometric mean is16. |
|
Answer» Correct Answer - 64 and 4 Let the two numbers be a and b. Then, A.M.=34 `rArr(a+b)/2=34` or a+b=68 G.M=16 `rArrsqrt(ab)=16` or ab=256 `therefore(a-b)^(2)=(a+b)^(2)-4ab` or `(a-b)^(2)=(68)^(2)-4xx256=3600` or a-b=60 (2) On solving (1) and (2), we get a= 64 and b=4. Hence, the required numbers are 64 and 4. |
|