Saved Bookmarks
| 1. |
Find value of sinx and cosy |
|
Answer» Answer: =>>>2^(sinx+cosy)=1 2^(sinx+cosy)=2^0 sinx+cosy=0 Sinx=-cosy =>>>16^(sin^2x+cos^y)=4 4^2(sin^2x+cos^2y)=4 2(sin^2x+cos^2y)=1 2(2*cos^2y)=1 Cos^2y=1/4 Cosy=1/2 Sinx=-1/2 |
|