1.

Find velocity of particle with 1 mg mass and having same wavelength that of electron moving with speed of 3xx10^(6) m/s. Mass of electron 9.1xx10^(-31) kg

Answer»

`2.7xx10^(-18) ms^(-1)`
`9xx10^(-2)ms^(-1)`
`3xx10^(-31) ms^(-1)`
`2.7xx10^(-21)ms^(-1)`

Solution :WAVELENGTH of particle ,
`(lambda_(1))=(h)/(mv)=(h)/((1xx10^(-3))xxv)`
Where V=velocity of particle
wavelength of electron ,
`(lambda_(2))=(h)/((9.1xx10^(-31))xx(3xx10^(6)))`but `lambda_(1)=lambda_(2)`
`therefore (h)/((1xx10^(-3))xxv)=(h)/((9.1xx10^(-31))xx(3xx10^(6)))` `therefore v=(9.1xx10^(-31)xx3xx10^(6))/(10^(-3))`
`=2.73xx10^(-21)ms^(-1)`


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