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Find whether the following equations have real roots. If real roots exist, find them `8x^(2)+2x-3=0`

Answer» Given equation is `8x^(2)+2x-3=0`
on comparing with `ax^(2)+bx+c=0` we get
`a=8,b=2` and `c=-3`
`:.` Discriminant `D=b^(2)-4ac`
`=(2)^(2)-4(8)(-3)`
`=4+96=100gt0`
Therefore the equation `8x^(2)+2x-3=0` has two distinct real roots because we know that if the equation `ax^(2)+bx+c=0` has discriminant greater than zero, then it has to distinct real roots.
Roots `x=(-b+-sqrt(D))/(2a)=(-2+-sqrt(100))/16=(-2+-10)/16`
`=(-2+10)/16,(-1-10)/16`
`=8/16,-12/16=1/2,-3/4`


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