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                                    Find whether the following equations have real roots. If real roots exist, find them `8x^(2)+2x-3=0` | 
                            
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Answer» Given equation is `8x^(2)+2x-3=0` on comparing with `ax^(2)+bx+c=0` we get `a=8,b=2` and `c=-3` `:.` Discriminant `D=b^(2)-4ac` `=(2)^(2)-4(8)(-3)` `=4+96=100gt0` Therefore the equation `8x^(2)+2x-3=0` has two distinct real roots because we know that if the equation `ax^(2)+bx+c=0` has discriminant greater than zero, then it has to distinct real roots. Roots `x=(-b+-sqrt(D))/(2a)=(-2+-sqrt(100))/16=(-2+-10)/16` `=(-2+10)/16,(-1-10)/16` `=8/16,-12/16=1/2,-3/4`  | 
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