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    				| 1. | 
                                    Find whether the following equations have real roots. If real roots exist, find them `-2x^(2)+3x+2=0` | 
                            
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Answer» Given equation is `-2x^(2)+3x+2=0` on comparing with `ax^(2)+bx+c=0` we get `a=-2,b=3` and `c=2`. `:.` Discriminant `D=b^(2)-4ac` `=(3)^(2)-4(-2)(2)` `=9+16=25gt0` Therefore, the equation `-2x^(2)+3x+2=0` has two distinct real roots because we know that if the equation `ax^(2)+bx+c=0` has its discriminant greater than zero, then it has two distinct real roots. Roots `x=(-b+-sqrt(D))/(2a)=(-3+-sqrt(25))/(2(-2))` `=(-3+-5)/(-4)=(-3+5)/(-4),(-3-5)/(-4)` `=2/(-4),(-8)/(-4)=-1/2,2`  | 
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