Find which of the following probability distribution is possible for a

1.	Find which of the following probability distribution is possible for a random variable :(i) x012P(x)0.40.40.2(ii) x012P(x)0.60.10.2(iii) x01234P(x)0.10.50.2-0.10.3
Answer» (i) Sum of probabilities = 0.4 + 0.4 + 0.2 = 1 Hence, given distribution is a probability distribution. (ii) Sum of probabilities = 0.6 + 0.1 + 0.2 = 0.9 ≠ 1 Hence, the given distribution is not a probability distribution. (iii) Here, one of the probability is – 0.1. which is negative. Hence, this distribution is not probability distribution.

Find which of the following probability distribution is possible for a random variable :(i) x012P(x)0.40.40.2(ii) x012P(x)0.60.10.2(iii) x01234P(x)0.10.50.2-0.10.3

Answer»

(i) Sum of probabilities = 0.4 + 0.4 + 0.2 = 1

Hence, given distribution is a probability distribution.

(ii) Sum of probabilities = 0.6 + 0.1 + 0.2 = 0.9 ≠ 1

Hence, the given distribution is not a probability distribution.

(iii) Here, one of the probability is – 0.1. which is negative.

Hence, this distribution is not probability distribution.

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Find which of the following probability distribution is possible for a random variable :(i) x012P(x)0.40.40.2(ii) x012P(x)0.60.10.2(iii) x01234P(x)0.10.50.2-0.10.3

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