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Find x^-3 if x = (100)^1-4 + (100)^0 |
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Answer» USE a^m÷a^n =(a)^m−n and (a^m)^n=(a) ^mn ⇒x=(100)^−3÷(100)^0 ⇒x=(100)^−3−0 ⇒x=(100)^−3 Now use, (a^m)^n=(a)^mn x^−3=[(100)^−3]^−3=(100)^9
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