Hey FRND....in the GIVEN figure...and in ∆ ACE AC = CEso.. so in ∆ ACE70° + z + z = 180°2z = 180-70z = 110/2z = 55°now in LINE CEB y + z = 180 y = 180-55y = 125°Now in ∆ AEB 20+125 + x = 180-145°x = 35°so the value of...x = 35°y = 125°HOPE THIS HELP YOU ☺☺❤❤❤❤
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