Find x pls it's urgent

1.	Find x pls it's urgent
Answer» ANSWER: in triangle COA SIDE OC = SIDE OA - > ( RADII OF SAME CIRCLE therefore by isosceles triangle theorem angle OCA = angle OAC. ( 1 ) ANGLE AOB IS EXTERIOR ANGLE OF TRIANGLE AOC THEREFORE BY THEOREM OF REMOTE INTERIOR ANGLE angle AOB = angle OAC + angle OCA 80⁰ = angle OAC + angle OAC -> [ from ( 1 ) ] 80⁰ = X + x 2 x = 80⁰ x = 80 / 2 x = 40⁰

Answer»

in triangle COA

SIDE OC = SIDE OA - > ( RADII OF SAME CIRCLE

therefore by isosceles triangle theorem

angle OCA = angle OAC. ( 1 )

ANGLE AOB IS EXTERIOR ANGLE OF TRIANGLE AOC

THEREFORE BY THEOREM OF REMOTE INTERIOR ANGLE

angle AOB = angle OAC + angle OCA

80⁰ = angle OAC + angle OAC -> [ from ( 1 ) ]

80⁰ = X + x

2 x = 80⁰

x = 80 / 2

x = 40⁰

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